ISS PREVIOUS YEAR 2016 PAPER-2 SOLUTION SET-A Q.NO. 13
- SWETA
- 2 hours ago
- 2 min read
ISS PREVIOUS YEAR 2016 PAPER-2 SOLUTION SET-A

Question 13
A company used three different methods to train its employees. The number of units of output produced by different employees trained by the three training methods are given below:
Method A: 50, 45, 55, 44Method B: 64, 48, 52, 56, 44Method C: 46, 42, 48, 45, 57, 42
The estimate of the population variance within the samples for the different methods is:
(a) 25.67 (b) 31.07 (c) 38.646 (d) 39.097
Solution
This question asks for Mean Square Error (MSE), i.e., Estimate of population variance within samples
Step 1: Compute ΣX²
For Method A:
50² + 45² + 55² + 44²= 2500 + 2025 + 3025 + 1936= 9486
For Method B:
64² + 48² + 52² + 56² + 44²= 4096 + 2304 + 2704 + 3136 + 1936= 14176
For Method C:
46² + 42² + 48² + 45² + 57² + 42²= 2116 + 1764 + 2304 + 2025 + 3249 + 1764= 13222
Total:
ΣX² = 9486 + 14176 + 13222ΣX² = 36884
Step 2: Correction Factor
T = 194 + 264 + 280 = 738
N = 15
C.F. = T² / N
C.F. = (738)² / 15
C.F. = 544644 / 15
C.F. = 36309.6
Step 3: Total Sum of Squares
SST = ΣX² − C.F.
SST = 36884 − 36309.6
SST = 574.4
Step 4: Sum of Squares Between Samples
SSB = (194² / 4 + 264² / 5 + 280² / 6) − 36309.6
SSB = (9409 + 13939.2 + 13066.67) − 36309.6
SSB = 105.27
Step 5: Sum of Squares Within Samples
SSE = SST − SSB
SSE = 574.4 − 105.27
SSE = 469.13
Step 6: Mean Square Within Samples
Degrees of freedom:
df = N − k = 15 − 3 = 12
MSE = SSE / df
MSE = 469.13 / 12
MSE = 39.094
≈ 39.097
Final Answer
(d) 39.097
Important Exam Insight
MSE represents: Estimate of population variance within samples (error variance)
In ANOVA:
MSB → Between groups variance
MSE → Within groups variance
ISS PREVIOUS YEAR 2016 PAPER-2 SOLUTION SET-A

Comments